0=(4x^2)-2x+10

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Solution for 0=(4x^2)-2x+10 equation: 



0=(4x^2)-2x+10

We move all terms to the left:

0-((4x^2)-2x+10)=0

We add all the numbers together, and all the variables

-(4x^2-2x+10)=0

We get rid of parentheses

-4x^2+2x-10=0

a = -4; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·(-4)·(-10)
Δ = -156
Delta is less than zero, so there is no solution for the equation

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